For the reaction N₂ + 3H₂ → 2NH₃, what mass of NH₃ forms from 56 g of N₂? (molar masses: N₂ = 28, NH₃ = 17 g/mol)

Answer and explanation

Correct answer: D. 68 g

  1. Step 1: Moles of N₂ = 56 ÷ 28 = 2 mol. Step 2. Using the mole ratio in N₂ + 3H₂ → 2NH₃ gives 68 g of NH₃. Answer: 68 g. Why not the others: 56 g is what you get if you assume equal masses of reactant and product. 34 g is what you get if you ignore the mole ratio. 136 g is what you get if you double the mole ratio.

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