A train moving at 15 m/s brakes with a constant deceleration of 8 m/s squared. What distance does it travel before stopping?

Answer and explanation

Correct answer: A. 14.062 m

  1. Step 1: Use v squared = u squared + 2as with v = 0.
  2. Step 2: s = 225/(2 x 8) = 14.062 m.
Answer
14.062 m.
Why not the others: 28.125 m, 1.875 m and 7.031 m do not fit.

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