How much 10 mol/L acid is needed to prepare 400 mL of 0.25 mol/L acid by dilution?
Answer and explanation
Correct answer: A. 10 mL
- Step 1: C1 V1 = C2 V2.
- Step 2: V1 = 0.25 x 400/10 = 10 mL.
Answer
10 mL.
Why not the others: 16000 mL, 390 mL and 25 mL do not fit.
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