What is the remainder when 9^17 is divided by 13?

Answer and explanation

Correct answer: B. 3

  1. Step 1: Find the repeating cycle of powers of 9 modulo 13. Step 2. Reducing the exponent 17 by the cycle length gives remainder 3. Answer: 3. Why not the others: 4 is what you get if you use a wrong cycle length. 5 is what you get if you use a wrong cycle length. 6 is what you get if you use a wrong cycle length.

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