6 dm³ of a gas at 200 K is brought to 300 K at constant pressure. What is the new volume?
Answer and explanation
Correct answer: D. 9 dm³
- Step 1: Charles's law: V₁/T₁ = V₂/T₂ (T in kelvin). Step 2. V₂ = 6 × 300 ÷ 200 = 9 dm³. Answer: 9 dm³. Why not the others: 4 dm³ is what you get if you invert the temperature ratio. 3 dm³ is what you get if you give only the size of the change in volume. 6 dm³ is what you get if you assume the volume stays constant.
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