Find the distance from the point (2, 3) to the line 3x+4y-6 = 0.

Answer and explanation

Correct answer: D. 12/5

  1. Step 1: Use d = |Ax0 + By0 + C| / sqrt(A^2 + B^2).
  2. Step 2: Numerator: |3(2) + 4(3) + (-6)| = 12. Denominator: sqrt(3^2 + 4^2) = 5.
  3. Step 3: d = 12/5.
Answer
12/5.
Why not the others: '12/7' divides by A + B instead of sqrt(A^2 + B^2); '12/25' divides by A^2 + B^2 without taking the square root; '22/5' mishandles the absolute value in the numerator.

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