A ball is kicked at 70 m/s at 45 degrees above level ground (g = 10 m/s^2, no air resistance). What is its horizontal range?

Answer and explanation

Correct answer: A. 490 m

  1. Step 1: The range is R = v^2 sin(2 theta) / g, and sin(90 degrees) = 1.
  2. Step 2: R = 70^2 x 1 / 10 = 490 m.
Answer
490 m.
Why not the others: '245 m' uses sin(45) instead of sin(90) = 1 in the range formula; '7 m' divides the speed by g without squaring it; '122.5 m' uses the maximum height formula instead.

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