Solve 2 sin x = sqrt(3) for 0 <= x < 2pi.
Answer and explanation
Correct answer: C. x = pi/3 and x = 2pi/3, where sin x = sqrt(3)/2
- Step 1: Isolate: sin x = sqrt(3)/2. Step 2. The reference angle is pi/3, and sine is positive in quadrants I and II: pi/3 and pi - pi/3 = 2pi/3. Answer: pi/3 and 2pi/3. Why not the others: pi/6 and 5pi/6 give sine 1/2, and 5pi/3 has a negative sine.
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