2.0 mol of an ideal gas occupies 4.1 L at 300 K. What is its pressure? (R = 0.0821 L atm per mol per K)
Answer and explanation
Correct answer: B. About 12 atm
- Step 1: Rearrange PV = nRT to P = nRT/V. Step 2. nRT = 2.0 x 0.0821 x 300 = 49.3 L atm. Step 3. P = 49.3 / 4.1 = 12 atm. Answer: about 12 atm. Why not the others: 6.0 atm and 24 atm come from halving or doubling n or R without reason, and 0.34 atm inverts the fraction.
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