Two cells, one of emf and internal resistance , the other of emf and internal resistance , are connected in parallel (like poles together) across an external resistor of . What is the current through the resistor?

Answer and explanation

Correct answer: B. 1.45 A

  1. Step 1: Let be the potential difference across the external resistor. By Kirchhoff's current law, the sum of currents delivered by the two cells equals the current through the load: .
  2. Step 2: Express currents in terms of : .
  3. Step 3: Combine like terms: .
  4. Step 4: Calculate current through the resistor: .
Answer
1.45 A.
Why not the others: results from simply taking the unweighted average emf , and erroneously treats the two cells as connected in series.

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