A Carnot engine has an efficiency of . When the temperature of its sink is lowered by (source unchanged), the efficiency becomes . What is the temperature of the source?

Answer and explanation

Correct answer: D. 500 K

  1. Step 1: Express the initial and modified Carnot efficiencies in terms of source temperature and sink temperature : and .
  2. Step 2: Subtract the first equation from the second equation: .
  3. Step 3: Solve for source temperature : .
Answer
500 K.
Why not the others: 300 K is the initial sink temperature ; 250 K is the reduced sink temperature; 600 K is an arithmetic error in the efficiency differential relation.

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