What is (1 + i)^2, where i is the imaginary unit with i^2 = -1?

Answer and explanation

Correct answer: B. 2i, because 1 + 2i + i^2 = 2i

  1. Step 1: Expand: (1 + i)^2 = 1 + 2i + i^2. Step 2. Since i^2 = -1, this is 2i. Answer: 2i. Why not the others: (a + b)^2 is not a^2 + b^2, and the real parts do cancel but the middle term stays.

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