What is the pH of a 0.01 mol/L solution of the strong acid HCl?
Answer and explanation
Correct answer: D. 2, because [H+] = 10^-2 mol/L
- Step 1: HCl dissociates completely, so [H+] = 0.01 = 10^-2 mol/L. Step 2. pH = -log(10^-2) = 2. Answer: 2. Why not the others: 12 would be a base, and pH is a logarithm of the concentration.
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