In a population in Hardy-Weinberg equilibrium 4% show a recessive trait. What percentage are carriers (heterozygotes)?
Answer and explanation
Correct answer: A. 32%
- Step 1: q^2 = 0.04 gives q = 0.2, so p = 0.8. Step 2. Carriers are 2pq = 2 x 0.8 x 0.2 = 0.32. Answer: 32%. Why not the others: The affected frequency is q^2, and carriers need the 2pq term.
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