A thief steals a car at 1:30 PM and drives off at a speed of 40 km/h. The theft is discovered at 2:00 PM, and the owner immediately chases the thief in another car at 50 km/h. At what time will the owner catch the thief?
Answer and explanation
Correct answer: A. 4:00 PM
- Step 1: Lead time = 2:00 PM - 1:30 PM = 30 minutes = 0.5 hours.
- Step 2: Head start distance = 40 km/h * 0.5 h = 20 km.
- Step 3: Relative speed of chase = 50 - 40 = 10 km/h.
- Step 4: Time required = 20 km / 10 km/h = 2 hours.
- Step 5: Catch time = 2:00 PM + 2 hours = 4:00 PM.
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