A ball is thrown vertically upward from the ground at . One second later a ball is released from rest at a height of directly above. Taking , the height above the ground at which the two balls meet is

Answer and explanation

Correct answer: B.

  1. Step 1: Set up the kinematic position equations with time measured from the release of ball . For ball : .
  2. Step 2: Ball is dropped from at , so for : .
  3. Step 3: Equate positions to find meeting time: .
  4. Step 4: Substitute into : .
Answer
.
Why not the others: occurs if the one-second release delay of ball is completely omitted.

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