Which transition metal ion exhibits an electronic configuration of [Ar] 3d^5 in its ground state?
Answer and explanation
Correct answer: D. Fe3+ and Mn2+
- Step 1: Fe is [Ar] 4s^2 3d^6; losing 2 4s and 1 3d electron gives Fe3+ = [Ar] 3d^5. Step 2. Mn is [Ar] 4s^2 3d^5; losing two 4s electrons gives Mn2+ = [Ar] 3d^5. Both have half-filled stable 3d^5 configurations. Answer: Fe3+ and Mn2+. Why not the others: Fe2+ is 3d^6, Cr3+ is 3d^3, Cu2+ is 3d^9.
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