According to the Arrhenius equation k = A * exp(-E_a / (RT)), what does a graph of ln(k) versus 1/T yield?
Answer and explanation
Correct answer: D. A straight line with slope equal to -E_a / R
- Step 1: Taking the natural logarithm: ln(k) = ln(A) - (E_a / R) (1/T). Step 2. This matches linear equation y = mx + c, where y = ln(k) and x = 1/T. Step 3. The slope m = -E_a / R, and the y-intercept is ln(A). Answer: A straight line with slope equal to -E_a / R. Why not the others:* The graph is linear, not parabolic or hyperbolic.
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