A Carnot heat engine operates between a high-temperature reservoir at 500 K and a low-temperature sink at 300 K. What is its maximum theoretical thermodynamic efficiency?
Answer and explanation
Correct answer: A. 40 percent
- Step 1: Carnot efficiency: eta = 1 - (T_C / T_H). Step 2. eta = 1 - (300 / 500) = 1 - 0.60 = 0.40 = 40%. Answer: 40 percent. Why not the others: 60% is T_C / T_H; 66.7% uses 500/300.
Practise more Thermodynamics and Electromagnetism.
Free questions with an explanation for every one, and full timed MDCAT Pakistan mock tests.
More Thermodynamics and Electromagnetism questions
- During an isothermal expansion of an ideal gas at temperature T, the volume doubles from V to 2 V. How much work is done by n moles of the g…
- Two point charges of +4.0 microcoulombs and -1.0 microcoulombs are separated by a distance of 30 cm in air. At what point along the line pas…
- A parallel-plate capacitor has capacitance C0 in vacuum. If a dielectric slab of dielectric constant kappa = 4.0 is inserted filling the gap…
- In a direct-current circuit, three resistors of 6 ohms, 12 ohms, and 4 ohms are connected in parallel across a 12 V battery. What is the tot…
- A proton moves with velocity v = 2.0 x 10^6 m/s perpendicular to a uniform magnetic field B = 0.50 T. What is the radius of its circular orb…
- What is the magnetic field B at the center of a long solenoid having 500 turns per meter carrying a current of 2.0 A? (Take mu_0 = 4*pi x 10…