A simple harmonic oscillator has amplitude A = 0.10 m and spring constant k = 200 N/m. What is its total mechanical energy?

Answer and explanation

Correct answer: B. 1.0 J

  1. Step 1: Total energy in SHM: E = (1/2) k A^2. Step 2. E = (1/2) 200 (0.10)^2 = 100 0.010 = 1.0 J. Answer: 1.0 J. Why not the others:* 2.0 J forgets the 1/2 factor; 20.0 J uses A instead of A^2.

Practise more Mechanics, Rotational Dynamics and Fluids.

Free questions with an explanation for every one, and full timed ECAT Pakistan mock tests.