A copper rod of length L = 0.50 m moves at constant speed v = 4.0 m/s perpendicular to a uniform magnetic field B = 0.60 T. What motional electromotive force (EMF) is induced across its ends?
Answer and explanation
Correct answer: A. 1.20 V
- Step 1: Motional EMF formula: E = B v L. Step 2. E = 0.60 T 4.0 m/s 0.50 m = 1.20 V. Answer: 1.20 V. Why not the others: 2.40 V forgets L = 0.50; 0.60 V halves the velocity.
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