A 12 V battery with internal resistance 1 ohm drives a 3 ohm resistor in series with a parallel pair of 6 ohm and 3 ohm resistors. What current flows through the 6 ohm resistor?

Answer and explanation

Correct answer: C. 0.67 A

  1. Step 1: The parallel pair is (6 x 3) / (6 + 3) = 2 ohm. Total resistance = 1 + 3 + 2 = 6 ohm.
  2. Step 2: Total current I = 12 / 6 = 2 A.
  3. Step 3: Voltage across the parallel pair = 2 A x 2 ohm = 4 V, so the current in the 6 ohm resistor = 4 / 6 = 0.67 A.
Answer
0.67 A.
Why not the others: 2.00 A is the total current; 1.33 A is the current in the 3 ohm resistor of the pair; 1.00 A comes from sharing the total current equally.

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