A mass of is attached to a spring of constant . What is the angular frequency of oscillation (in rad/s)?
Answer and explanation
Correct answer: D. 6
- Step 1: For a frictionless horizontal spring-mass oscillator, the natural angular frequency is given by .
- Step 2: Substitute spring stiffness and mass : .
- Step 3: Taking the square root gives .
Answer
6.
Why not the others: 36 calculates without taking the square root; 1/36 inverts without square root; 12 divides by 3 instead of taking square root.
Practise more Oscillations.
Free questions with an explanation for every one, and full timed NEET UG mock tests.
More Oscillations questions
- A mass of is attached to a spring of constant . What is the angular frequency of oscillation (in rad/s)?
- A mass of is attached to a spring of constant . What is the angular frequency of oscillation (in rad/s)?
- A spring of constant is cut into two pieces whose lengths are in the ratio . A block is attached to th…
- A block of mass rests on a block of mass that is attached to a spring of constant and oscill…
- A mass of is attached to a spring of constant . What is the angular frequency of oscillation (in rad/s)?