What is the calculated 'spin-only' magnetic moment (in Bohr Magnetons, BM) for the complex ion [Fe(H2O)6]2+?
Answer and explanation
Correct answer: C. 4.90 BM
- Step 1: In , iron is in the +2 oxidation state (: ).
- Step 2: Water () is a weak field ligand, so , producing a high-spin octahedral complex with electron configuration .
- Step 3: The number of unpaired electrons is (one paired pair in , three unpaired in , and two unpaired in ).
- Step 4: The spin-only magnetic moment is calculated as .
Answer
4.90 BM
Why not the others: '1.73 BM' corresponds to 1 unpaired electron (); '2.83 BM' corresponds to 2 unpaired electrons (); '5.92 BM' corresponds to 5 unpaired electrons (, as in high-spin ).
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