Using the Nernst equation at 298 K, what is the cell potential (Ecell) of a Daniell cell: Zn | Zn2+(0.01 M) || Cu2+(1.0 M) | Cu, given E°cell = 1.10 V?

Answer and explanation

Correct answer: D. 1.159 V

  1. Step 1: Write the overall balanced cell reaction: , where .
  2. Step 2: The Nernst equation at 298 K is: .
  3. Step 3: Substitute the values: .
  4. Step 4: Since : .
Answer
1.159 V
Why not the others: '1.041 V' incorrectly adds a negative sign (); '1.100 V' is the standard potential when both concentrations are 1.0 M; '1.218 V' incorrectly multiplies by 4 instead of 2.

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