An inductor of self-inductance L = 2.0 H carries a steady current that increases uniformly from 0 to 4.0 A. What is the magnetic energy stored in the magnetic field of the inductor when the current reaches 4.0 A?
Answer and explanation
Correct answer: B. 16.0 J
- Step 1: The magnetic potential energy stored in an inductor of inductance carrying current is given by the formula: .
- Step 2: Substitute the given values: and .
- Step 3: .
Answer
16.0 J
Why not the others: '8.0 J' calculates or ; '4.0 J' calculates omitting ; '32.0 J' forgets the factor of and computes .
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