Which of the following bonds exhibits the greatest ionic character based on Pauling electronegativity differences?
Answer and explanation
Correct answer: C. Na–F
- Step 1: Calculate electronegativity differences: Na (0.93) and F (3.98) give .
- Step 2: H-F has ; C-Cl has ; C-H has . The largest difference yields the highest ionic character.
Answer
Na–F.
Why not the others: H-F is polar covalent; C-Cl and C-H are covalent bonds with low electronegativity differences.
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