How many sigma (σ) and pi (π) bonds are present in a single molecule of propene (CH₃–CH=CH₂)?

Answer and explanation

Correct answer: B. 8 sigma bonds and 1 pi bond

  1. Step 1: Count all bonds: 6 C–H single bonds (6 σ) + 1 C–C single bond (1 σ) + 1 C=C double bond (1 σ, 1 π).
  2. Step 2: Sum the bonds: total sigma = bonds, and total pi = bond.
Answer
8 sigma bonds and 1 pi bond.
Why not the others: 9 sigma neglects the double bond pi component; 7 sigma misses one C-H bond; 6 sigma omits the C-C backbone sigma bonds.

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