Berapakah pH dari larutan asam kuat asam klorida HCl berkonsentrasi 0,001 M pada suhu 25 °C?

Answer and explanation

Correct answer: C. 3

[H+] = M = 0,001 = 10^-3 M. pH = -log[H+] = -log(10^-3) = 3.

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