What is the solubility product expression K_sp for sparingly soluble silver phosphate, Ag3PO4?
Answer and explanation
Correct answer: A. K_sp = [Ag+]^3 * [PO4^3-]
- Step 1: Dissolution equilibrium: Ag3PO4(s) <=> 3 Ag+(aq) + PO4^3-(aq). Step 2. By law of mass action, pure solids have unit activity, giving K_sp = [Ag+]^3 [PO4^3-]. Answer: K_sp = [Ag+]^3 [PO4^3-]. Why not the others:** Stoichiometric coefficients appear as exponents in the equilibrium constant expression.
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