Cement and sand are mixed in the ratio 3:5 by mass. A builder needs 120 kg of mixture. How many kilograms of sand are needed?
Answer and explanation
Correct answer: B. 75 kg
- Step 1: The ratio has 3+5 = 8 parts, so one part = 120/8 = 15 kg. Step 2. Sand is 5 parts = 5 x 15 = 75 kg. Answer: 75 kg. Why not the others: 45 kg is the mass of cement, not sand; 24 kg divides by the sand part alone (5); 200 kg multiplies the total by 5/3 instead of by 5/8.
Practise more Calculations from tables (set 2).
Free questions with an explanation for every one, and full timed UCAT mock tests.
More Calculations from tables (set 2) questions
- A stall buys scarves and sells them. What is the total profit in pounds?
- A bag has a list price of GBP 60 before VAT. A 20% discount is taken off the list price, and then VAT at 20% is added to the discounted pric…
- A van travels 200 km. What is the fuel cost of the journey in pounds?
- Monthly orders at a bakery: Between which two consecutive months was the percentage increase largest?
- Three sizes of cereal are sold. Which size has the lowest price per 100 g?
- In a sale all items are 30% off. A coat is now priced at GBP 140. What was its price before the sale?