A fuel transfers 25.1 kJ to 0.50 kg of water (c = 4.18 kJ/kg/°C). What is the temperature rise?

Answer and explanation

Correct answer: B. 12 °C

  1. Step 1: Rearrange Eh = cmΔT: ΔT = Eh ÷ (c × m).
  2. Step 2: 25.1 ÷ (4.18 × 0.50) = 25.1 ÷ 2.09 = 12 °C.
Answer
12 °C.
Why not the others: 50 °C: the specific heat capacity was left out. 105 °C: the energy was multiplied by c. 6 °C: the mass of water was ignored.

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