Leaving Cert Ireland · Chemistry

Mole Calculations

14 practice questions, each with the answer and an explanation.

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Random questions from this topic, one at a time. You see the answer and the explanation straight after each one.

All 14 questions

  1. Find the relative formula mass of CH. (H = 1, C = 12, N = 14, O = 16, Na = 23, Mg = 24, Al = 27, S = 32, Cl = 35.5, K = 39, Ca = 40, Fe = 56, Cu = 63.5, Zn = 65, Ag = 108)
  2. Find the relative formula mass of Ca(OH). (H = 1, C = 12, N = 14, O = 16, Na = 23, Mg = 24, Al = 27, S = 32, Cl = 35.5, K = 39, Ca = 40, Fe = 56, Cu = 63.5, Zn = 65, Ag = 108)
  3. How many moles are present in 39.875 g of CuSO? (Relative formula mass = 159.5)
  4. How many moles are present in 300 g of CaCO? (Relative formula mass = 100)
  5. How many moles are present in 8 g of NaOH? (Relative formula mass = 40)
  6. How many moles are present in 29 g of Mg(OH)? (Relative formula mass = 58)
  7. How many moles are present in 4 g of NaOH? (Relative formula mass = 40)
  8. Calculate the percentage by mass of O in Ca(OH). (H = 1, C = 12, N = 14, O = 16, Mg = 24, S = 32, Cl = 35.5, Al = 27, Ca = 40, Fe = 56, Cu = 63.5, Na = 23)
  9. 25 cm of 0.5 mol/dm hydrochloric acid is diluted with water to a total volume of 200 cm. What is the new concentration?
  10. 10 cm of 1 mol/dm hydrochloric acid is diluted with water to a total volume of 200 cm. What is the new concentration?
  11. 100 cm of 10 mol/dm hydrochloric acid is diluted with water to a total volume of 1000 cm. What is the new concentration?
  12. 20 cm of 1 mol/dm hydrochloric acid is diluted with water to a total volume of 250 cm. What is the new concentration?
  13. 50 cm of 0.5 mol/dm hydrochloric acid is diluted with water to a total volume of 200 cm. What is the new concentration?
  14. 200 g of calcium carbonate reacts completely according to CaCO → CaO + CO. What mass of calcium oxide is formed? (Relative masses: calcium carbonate 100, calcium oxide 56.)

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