A Carnot engine operates between reservoirs at 600 K and 300 K. What is its thermodynamic efficiency?
Answer and explanation
Correct answer: D. 50%
- Step 1: Efficiency eta = 1 - T_C / T_H. Step 2. eta = 1 - 300 / 600 = 1 - 0.5 = 0.5 = 50%. Answer: 50%. Why not the others: 100% requires T_C = 0 K; 25% divides incorrectly; 75% uses (600 - 150)/600.
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