A mass of 2.0 kg attached to a spring oscillates with spring constant k = 200 N/m. What is the angular frequency omega of the oscillation?

Answer and explanation

Correct answer: C. 10 rad/s

  1. Step 1: Recall the formula for angular frequency in simple harmonic motion: omega = sqrt(k / m).
  2. Step 2: Substitute given parameters: k = 200 N/m, m = 2.0 kg.
  3. Step 3: Calculate quotient: k / m = 200 / 2.0 = 100.
  4. Step 4: Take square root: omega = sqrt(100) = 10 rad/s.
Answer
10 rad/s.
Why not the others: '100 rad/s' forgets to take the square root of k/m; '5 rad/s' computes k / (2m10); '20 rad/s' multiplies mass by 10.

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