What is the work done on an ideal gas during an isobaric expansion from 0.02 m^3 to 0.05 m^3 at a constant pressure of 100,000 Pa?

Answer and explanation

Correct answer: D. 3,000 J

  1. Step 1: Work done during isobaric process is W = P * delta_V.
  2. Step 2: Calculate change in volume: delta_V = V_final - V_initial = 0.05 - 0.02 = 0.03 m^3.
  3. Step 3: Multiply by pressure: W = 100,000 Pa * 0.03 m^3 = 3,000 J.
Answer
3,000 J.
Why not the others: '5,000 J' uses V_final alone; '2,000 J' uses V_initial alone; '7,000 J' adds both volumes together.

Practise more Mechanics, Waves and Electromagnetism.

Free questions with an explanation for every one, and full timed General Education Diploma (GED Oman) mock tests.

All Mechanics, Waves and Electromagnetism questionsTake a mock test

More Mechanics, Waves and Electromagnetism questions