What volume of 2.0 M hydrochloric acid (HCl) stock solution is needed to prepare 500 mL of a 0.20 M HCl working solution?
Answer and explanation
Correct answer: B. 50 mL
Using the dilution equation M1 V1 = M2 V2: (2.0 M) V1 = (0.20 M) (500 mL). Solving for V1 gives V1 = (0.20 * 500) / 2.0 = 100 / 2.0 = 50 mL.
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