A diver descends to a depth of 20 m in fresh water (density = 1,000 kg/m^3). Taking atmospheric pressure P0 = 1.0 x 10^5 Pa and g = 10 m/s^2, what is the absolute hydrostatic pressure experienced by the diver?

Answer and explanation

Correct answer: D. 3.0 x 10^5 Pa

Absolute pressure at depth h is given by P = P0 + rho g h. The gauge pressure is rho g h = (1,000 kg/m^3) (10 m/s^2) (20 m) = 2.0 x 10^5 Pa. Adding atmospheric pressure: P = 1.0 x 10^5 Pa + 2.0 x 10^5 Pa = 3.0 x 10^5 Pa (approx 3 atmospheres).

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