In a hydraulic lift, the smaller piston has an area of 10 cm^2 and the larger piston has an area of 500 cm^2. If a downward force of 100 N is applied to the small piston, what upward load can the large piston support?

Answer and explanation

Correct answer: D. 5,000 N

By Pascal's principle, pressure is transmitted undiminished through an enclosed fluid: P1 = P2 => F1 / A1 = F2 / A2. Rearranging for F2: F2 = F1 (A2 / A1) = 100 N (500 cm^2 / 10 cm^2) = 100 N * 50 = 5,000 N.

Practise more Classical Mechanics, Fluids, Thermodynamics, and Waves.

Free questions with an explanation for every one, and full timed Toelatingsexamen Arts & Tandarts België (Medical & Dental Entrance Exam) mock tests.