An object of volume 0.0020 m^3 is completely submerged in water (density = 1,000 kg/m^3). Taking g = 10 m/s^2, what is the buoyant force exerted by the water on the object?
Answer and explanation
Correct answer: A. 20 N
According to Archimedes' principle, the buoyant force equals the weight of the displaced fluid: F_b = rho_fluid V_submerged g = 1,000 kg/m^3 0.0020 m^3 10 m/s^2 = 20 N.
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