How much heat energy is required to raise the temperature of 2.0 kg of liquid water from 20 °C to 50 °C, given the specific heat capacity of water c = 4,184 J/(kg·K)?
Answer and explanation
Correct answer: D. 251.0 kJ
Using the sensible heat equation q = m c ΔT: q = (2.0 kg) (4,184 J/(kg·K)) (50 °C - 20 °C) = 2.0 4,184 30 = 251,040 J ≈ 251.0 kJ.
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