Two resistors of 12 Ω and 4 Ω are connected in parallel. What is their combined resistance?
Answer and explanation
Correct answer: C. 3 Ω
- Step 1: For parallel resistors 1/R = 1/R₁ + 1/R₂, so R = R₁R₂/(R₁ + R₂). Step 2. R = 12 × 4 ÷ 16 = 3 Ω. Answer: 3 Ω. Why not the others: 16 Ω is what you get if you add them as in series. 8 Ω is what you get if you take the average. 48 Ω is what you get if you multiply them.
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