In a population in Hardy-Weinberg equilibrium, the frequency of the recessive allele is 0.3. What is the frequency of heterozygotes?
Answer and explanation
Correct answer: B. 0.42
- Step 1: 2pq = 2 x 0.7 x 0.3 = 0.42. Answer: 0.42. Why not the others: 0.09 is q squared, 0.49 is p squared and 0.21 is pq.
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