A 2.0 kg block on a bench is pushed by a 12 N force while a constant friction force of 4.0 N opposes motion. What is its acceleration?
Answer and explanation
Correct answer: A. 4.0 m/s squared
- Step 1: Net force = 12 - 4.0 = 8.0 N. Step 2. a = F/m = 8.0 / 2.0 = 4.0 m/s squared. Answer: 4.0 m/s squared. Why not the others: 6.0 m/s squared ignores friction, 8.0 is the net force without dividing by mass, and 2.0 mixes up the quantities.
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