Two parents are both AaBb for independently assorting genes. What is the probability of an offspring that is aa and shows the dominant trait for B (aaB_)?
Answer and explanation
Correct answer: C. 3/16
- Step 1: and for independent genes. Step 2. Multiply: . Answer: 3/16. Why not the others: 1/16 is aabb; 9/16 is A_B_; 3/8 adds the aaB_ and A_bb classes.
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