Two dice are thrown simultaneously. What is the probability that the sum of the two numbers appearing on top is a prime number?

Answer and explanation

Correct answer: D. 5/12

- Sum 2: (1,1) [1]
- Sum 3: (1,2), (2,1) [2]
- Sum 5: (1,4), (2,3), (3,2), (4,1) [4]
- Sum 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) [6]
- Sum 11: (5,6), (6,5) [2]
  1. Step 1: Total outcomes = 6 * 6 = 36.
  2. Step 2: Prime sums possible between 2 and 12 are: 2, 3, 5, 7, 11.
  3. Step 3: Total favorable outcomes = 1 + 2 + 4 + 6 + 2 = 15.
  4. Step 4: Probability = 15 / 36 = 5/12.
Why not the others: Other values result from miscounting the favorable outcomes in the sample space, inverting the probability fraction, or confusing independent with mutually exclusive events.

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