Jumlah 10 suku pertama deret aritmetika dengan suku pertama a = 5 dan beda b = 3 adalah...

Answer and explanation

Correct answer: D. Jumlah sepuluh suku pertama S10 = 185

S10 = 10/2 × [2(5) + (10 - 1)×3] = 5 × [10 + 27] = 5 × 37 = 185.

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