What is the standard cell potential for a Daniell cell: Zn(s) | Zn^2+(aq, 1M) || Cu^2+(aq, 1M) | Cu(s)? (E^0(Zn2+/Zn) = -0.76 V, E^0(Cu2+/Cu) = +0.34 V)
Answer and explanation
Correct answer: A. +1.10 V
- Step 1: Cathode (reduction): Cu^2+ + 2e^- -> Cu (E^0 = +0.34 V). Anode (oxidation): Zn -> Zn^2+ + 2e^- (E^0 = -0.76 V). Step 2. E^0_cell = E^0_cathode - E^0_anode = +0.34 V - (-0.76 V) = +1.10 V. Answer: +1.10 V. Why not the others: Standard cell potential must be positive for a spontaneous galvanic cell.
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