A reaction has rate = k[A][B]^2. What happens to the rate if the concentration of B is doubled?
Answer and explanation
Correct answer: B. It increases by a factor of 4
- Step 1: The order with respect to B is 2. Step 2. Doubling B multiplies the rate by . Answer: It increases by a factor of 4. Why not the others: doubling would be right for first order; a factor of 8 would be third order; the rate does depend on B.
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