A plot of ln k against 1/T has a gradient of -6000 K. What is the activation energy? (R = 8.31 J K-1 mol-1)
Answer and explanation
Correct answer: D. 49.9 kJ mol-1
- Step 1: Gradient , so J mol-1. Step 2. Activation energy is positive: kJ mol-1. Answer: 49.9 kJ mol-1. Why not the others: 722 divides by R; -49.9 keeps the sign of the gradient; 499 is a factor-of-ten slip.
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